n^2-4n+7/4=0

Solution for n^2-4n+7/4=0 equation:

n^2-4n+7/4=0

We multiply all the terms by the denominator


n^2*4-4n*4+7=0

Wy multiply elements

4n^2-16n+7=0

a = 4; b = -16; c = +7;
Δ = b2-4ac
Δ = -162-4·4·7
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-12}{2*4}=\frac{4}{8}
=1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+12}{2*4}=\frac{28}{8}
=3+1/2
$